0 Ml Of 0 120 M Naoh Is Added To 565 Ml Of 0 200 M Weak Acid Ka 8 25 10 5 What I

Find answers on: 0 ml of 0.120 m naoh is added to 565 ml of 0.200 m weak acid (ka = 8.25 × 10-5). what is the ph of the resulting buffer?.

0 ml of 0.120 m naoh is added to 565 ml of 0.200 m weak acid (ka = 8.25 × 10-5). what is the ph of the resulting buffer?

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